Subtract the Product and Sum of Digits of an Integer
给一个数, 返回它的每个位上的数的积和和的差.
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class Solution { public int subtractProductAndSum(int n) { int p = 1; int s = 0; while(n > 0) { p *= n % 10; s += n % 10; n /= 10; } return p - s; } } |