Shuffle the Array
给一个array, 一共2n个元素, 求重组后的array, 让前n个元素和后n个元素互相交叉.
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class Solution { public: vector<int> shuffle(vector<int>& nums, int n) { vector<int> res; for(int i = 0; i < n; i++) { res.push_back(nums[i]); res.push_back(nums[n+i]); } return res; } }; |