Largest Number After Digit Swaps by Parity
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class Solution { public int largestInteger(int num) { String s = ""+num; char[] c = s.toCharArray(); int n = c.length; LinkedList<Integer> odd = new LinkedList<>(); LinkedList<Integer> even = new LinkedList<>(); int cc = 0; while(num != 0){ if((num % 10) % 2 == 0) even.add(num % 10); else odd.add(num % 10); cc++; num /= 10; } Collections.sort(odd, Collections.reverseOrder()); Collections.sort(even, Collections.reverseOrder()); int i = 0; int j = 0; for(int ii = 0; ii < n; ii++) { if((c[ii] - '0') % 2 == 0) c[ii] =(char)('0' + even.removeFirst()); else c[ii] =(char)('0' + odd.removeFirst()); } return Integer.valueOf(String.valueOf(c)); } } |