Groups of Special-Equivalent Strings
给一个string组, 找其中有几对儿group, 每个group中的string交换奇数or偶数index上的char后相等. 直接counting就可以.
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class Solution { public int numSpecialEquivGroups(String[] A) { Set<String> seen = new HashSet(); for (String S: A) { int[] count = new int[52]; for (int i = 0; i < S.length(); ++i) count[S.charAt(i) - 'a' + 26 * (i % 2)]++; seen.add(Arrays.toString(count)); } return seen.size(); } } |