Foregone Solution
原题地址: https://codingcompetitions.withgoogle.com/codejam/round/0000000000051705/0000000000088231
看到4就拆分成2+2, 看别的就0+x, 注意leading zero.
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import java.util.Scanner; public class Solution { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int n = Integer.valueOf(scanner.nextLine()); for (int i = 1; i <= n; i++) { String[] res = solve(scanner.nextLine()); System.out.println("Case #" + i + ": " + res[0]+ " " + res[1]); } } private static String[] solve(String n){ StringBuilder sb1 = new StringBuilder(); StringBuilder sb2 = new StringBuilder(); for(int i = 0; i < n.length(); i++) { if (n.charAt(i) == '4'){ sb1.append('1'); sb2.append('3'); } else{ sb1.append(n.charAt(i)); sb2.append('0'); } } int count = 0; while(count < sb2.length() && sb2.charAt(count) == '0') { count++; } sb2.delete(0, count); if (sb2.length() == 0) { sb2.append('0'); } return new String[]{sb1.toString(), sb2.toString()}; }; } |