Count Integers With Even Digit Sum
给一个range[1,num], 求里面有多少数的digit sum是偶数.
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class Solution { public int countEven(int num) { int res = 0; for(int i = 1; i <= num; i++){ int even = 0; int cur = i; while(cur != 0){ even += (cur % 10); cur /= 10; } if(even % 2 == 0) res++; } return res; } } |